The fourth ring of the capacitor
SOLUTION (A) How long does it take the charge on the capacitor to reduce to one-fourth its initial value? Apply the discharging capacitor g(t) = Qe-t/RC equation Substitute q(t) = Q/4 into the preceding equation and cancel Q Take natural logarithms of both sides In(l/4) =-t/RC and solve for the time t t=-RC In(1/4) = 1.39RC= 1.39τ (B) Compute the initial charge and time constant from …